![Show that the General Solution of the Differential Equation `Dy/Dx + (Y^2 + Y +1)/(X^2 + X + 1) = 0` Is Given by (X + Y + 1) = A (1 – X – Y – 2xy), Where A Is Parameter - Mathematics | Shaalaa.com Show that the General Solution of the Differential Equation `Dy/Dx + (Y^2 + Y +1)/(X^2 + X + 1) = 0` Is Given by (X + Y + 1) = A (1 – X – Y – 2xy), Where A Is Parameter - Mathematics | Shaalaa.com](https://www.shaalaa.com/images/_4:2f090800e6e947a3a38f0191f4c6ea11.png)
Show that the General Solution of the Differential Equation `Dy/Dx + (Y^2 + Y +1)/(X^2 + X + 1) = 0` Is Given by (X + Y + 1) = A (1 – X – Y – 2xy), Where A Is Parameter - Mathematics | Shaalaa.com
![If | x | < 1 and | y | < 1, then the sum of infinity of the series (x + y) + (x^2 + xy + y^2) + (x^3 + x^2y + xy^2 + y^3) + ..... to ∞ is If | x | < 1 and | y | < 1, then the sum of infinity of the series (x + y) + (x^2 + xy + y^2) + (x^3 + x^2y + xy^2 + y^3) + ..... to ∞ is](https://haygot.s3.amazonaws.com/questions/1985539_1255658_ans_a4da1a92ffd74b5895a27a49ebadfa89.jpeg)
If | x | < 1 and | y | < 1, then the sum of infinity of the series (x + y) + (x^2 + xy + y^2) + (x^3 + x^2y + xy^2 + y^3) + ..... to ∞ is
SOLUTION: Graph y=(1/3)^x. Identify the domain, asymptote, and range. Did I do this right? x=3 -2 -1 0 1 2 3 y=27 9 3 1 1/3 1/9 1/27 Domain=all real #s asymptote=y=
![graphing functions - Interpret the graph of $\frac{ax+b}{cx+d}$ as a transformation of $y=\frac{1}{x}$ - Mathematics Stack Exchange graphing functions - Interpret the graph of $\frac{ax+b}{cx+d}$ as a transformation of $y=\frac{1}{x}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/Zww7y.png)